x+5x^2+20=2x^2

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Solution for x+5x^2+20=2x^2 equation: 



x+5x^2+20=2x^2

We move all terms to the left:

x+5x^2+20-(2x^2)=0

determiningTheFunctionDomain
5x^2-2x^2+x+20=0

We add all the numbers together, and all the variables

3x^2+x+20=0

a = 3; b = 1; c = +20;
Δ = b2-4ac
Δ = 12-4·3·20
Δ = -239
Delta is less than zero, so there is no solution for the equation

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